Try making your formula accept vectorized inputs.
If you want the actual double values instead of it being represented as sym, you'll need to cast the output using double().įirst off, let's avoid using the symbolic math toolbox for this. Bear in mind that this is only for a single vector. This is really the only way I can see this without using a for loop. This isn't exactly what you want, but you can simply choose all of the elements along the diagonal when you specify the input as a column vector as your output, as this would exactly correspond the i'th entry of the element in your vector with the i'th formula. If you did out = subs(f,), this will give you a 9 x 1 vector, where each trio of three is the output for that particular x value. In other words, if you did out = subs(f, ), this will output a matrix where the first row consists of x=1, the next row consists of x=2 and the last row consists of x=3. The crux behind this is that for each value of x you want to use for substituting, it will replace the entire formula with x. If you want to use a vector, it's important that you specify this as a column vector.
Val can be a single value, vector or matrix of values that you wish to substitute the variables in your formula with. subs has syntax like so: out = subs(f, val) You can then use subs to substitute values of x with values that you want. First, create your formula as normal: syms x This is an additional answer to your question, supposing that we had to use the symbolic math toolbox instead.
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